return elements that match specified CSS selector(s)

How do I remove elements from the DOM that were selected with querySelectorAll()?

Answers:

  • To remove elements from the DOM that you select using querySelectorAll(), you can iterate over the NodeList returned by querySelectorAll() and then remove each selected element from its parent node. Here's how you can do it:

    Example Code:

    // Select elements using querySelectorAll
const elements = document.querySelectorAll('.your-class-name');

elements.forEach(element => {
    // Remove each element from its parent
    element.parentNode.removeChild(element);
});

// Alternatively, you can use `remove()` method directly
elements.forEach(element => {
    element.remove();
});

    Explanation:

    1. Selecting Elements: querySelectorAll('.your-class-name') selects all elements with the specified class name. This returns a NodeList of elements.

    2. Iterating Over the NodeList: You can use the forEach() method to iterate over each element in the NodeList.

    3. Removing Elements:

      • Using removeChild(): You get the parent node of the element with element.parentNode and then call removeChild(element) on that parent to remove the element.
      • Using remove(): You can also call the remove() method directly on the element itself, which simplifies the code.

    Note:

    • If you are removing multiple elements from the DOM frequently, consider the performance implications, especially if the selection results in a large number of elements.

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